Integrand size = 27, antiderivative size = 200 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {13 d^6 x \sqrt {d^2-e^2 x^2}}{128 e^4}+\frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {13 d^8 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{128 e^5} \]
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Time = 0.18 (sec) , antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.259, Rules used = {866, 1823, 847, 794, 201, 223, 209} \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {13 d^8 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{128 e^5}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {13 d^6 x \sqrt {d^2-e^2 x^2}}{128 e^4}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3} \]
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Rule 201
Rule 209
Rule 223
Rule 794
Rule 847
Rule 866
Rule 1823
Rubi steps \begin{align*} \text {integral}& = \int x^4 (d-e x)^2 \sqrt {d^2-e^2 x^2} \, dx \\ & = -\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}-\frac {\int x^4 \left (-13 d^2 e^2+16 d e^3 x\right ) \sqrt {d^2-e^2 x^2} \, dx}{8 e^2} \\ & = \frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {\int x^3 \left (-64 d^3 e^3+91 d^2 e^4 x\right ) \sqrt {d^2-e^2 x^2} \, dx}{56 e^4} \\ & = -\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}-\frac {\int x^2 \left (-273 d^4 e^4+384 d^3 e^5 x\right ) \sqrt {d^2-e^2 x^2} \, dx}{336 e^6} \\ & = \frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {\int x \left (-768 d^5 e^5+1365 d^4 e^6 x\right ) \sqrt {d^2-e^2 x^2} \, dx}{1680 e^8} \\ & = \frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {\left (13 d^6\right ) \int \sqrt {d^2-e^2 x^2} \, dx}{64 e^4} \\ & = \frac {13 d^6 x \sqrt {d^2-e^2 x^2}}{128 e^4}+\frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {\left (13 d^8\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx}{128 e^4} \\ & = \frac {13 d^6 x \sqrt {d^2-e^2 x^2}}{128 e^4}+\frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {\left (13 d^8\right ) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right )}{128 e^4} \\ & = \frac {13 d^6 x \sqrt {d^2-e^2 x^2}}{128 e^4}+\frac {8 d^3 x^2 \left (d^2-e^2 x^2\right )^{3/2}}{35 e^3}-\frac {13 d^2 x^3 \left (d^2-e^2 x^2\right )^{3/2}}{48 e^2}+\frac {2 d x^4 \left (d^2-e^2 x^2\right )^{3/2}}{7 e}-\frac {1}{8} x^5 \left (d^2-e^2 x^2\right )^{3/2}+\frac {d^4 (1024 d-1365 e x) \left (d^2-e^2 x^2\right )^{3/2}}{6720 e^5}+\frac {13 d^8 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{128 e^5} \\ \end{align*}
Time = 0.40 (sec) , antiderivative size = 136, normalized size of antiderivative = 0.68 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (2048 d^7-1365 d^6 e x+1024 d^5 e^2 x^2-910 d^4 e^3 x^3+768 d^3 e^4 x^4+1960 d^2 e^5 x^5-3840 d e^6 x^6+1680 e^7 x^7\right )-2730 d^8 \arctan \left (\frac {e x}{\sqrt {d^2}-\sqrt {d^2-e^2 x^2}}\right )}{13440 e^5} \]
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Time = 0.40 (sec) , antiderivative size = 130, normalized size of antiderivative = 0.65
method | result | size |
risch | \(\frac {\left (1680 e^{7} x^{7}-3840 d \,e^{6} x^{6}+1960 d^{2} e^{5} x^{5}+768 d^{3} e^{4} x^{4}-910 d^{4} e^{3} x^{3}+1024 d^{5} e^{2} x^{2}-1365 d^{6} e x +2048 d^{7}\right ) \sqrt {-e^{2} x^{2}+d^{2}}}{13440 e^{5}}+\frac {13 d^{8} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{128 e^{4} \sqrt {e^{2}}}\) | \(130\) |
default | \(\frac {-\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {7}{2}}}{8 e^{2}}+\frac {d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{6}+\frac {5 d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4}+\frac {3 d^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )}{8 e^{2}}}{e^{2}}+\frac {3 d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {5}{2}}}{6}+\frac {5 d^{2} \left (\frac {x \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4}+\frac {3 d^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )}{e^{4}}+\frac {2 d \left (-e^{2} x^{2}+d^{2}\right )^{\frac {7}{2}}}{7 e^{5}}+\frac {d^{4} \left (\frac {\left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {7}{2}}}{3 d e \left (x +\frac {d}{e}\right )^{2}}+\frac {5 e \left (\frac {\left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {5}{2}}}{5}+d e \left (-\frac {\left (-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e \right ) \left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}{8 e^{2}}+\frac {3 d^{2} \left (-\frac {\left (-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e \right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}{4 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )\right )}{3 d}\right )}{e^{6}}-\frac {4 d^{3} \left (\frac {\left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {5}{2}}}{5}+d e \left (-\frac {\left (-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e \right ) \left (-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}{8 e^{2}}+\frac {3 d^{2} \left (-\frac {\left (-2 \left (x +\frac {d}{e}\right ) e^{2}+2 d e \right ) \sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}{4 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-\left (x +\frac {d}{e}\right )^{2} e^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )\right )}{e^{5}}\) | \(696\) |
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Time = 0.36 (sec) , antiderivative size = 128, normalized size of antiderivative = 0.64 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=-\frac {2730 \, d^{8} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) - {\left (1680 \, e^{7} x^{7} - 3840 \, d e^{6} x^{6} + 1960 \, d^{2} e^{5} x^{5} + 768 \, d^{3} e^{4} x^{4} - 910 \, d^{4} e^{3} x^{3} + 1024 \, d^{5} e^{2} x^{2} - 1365 \, d^{6} e x + 2048 \, d^{7}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{13440 \, e^{5}} \]
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Time = 2.03 (sec) , antiderivative size = 340, normalized size of antiderivative = 1.70 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=d^{2} \left (\begin {cases} \frac {d^{6} \left (\begin {cases} \frac {\log {\left (- 2 e^{2} x + 2 \sqrt {- e^{2}} \sqrt {d^{2} - e^{2} x^{2}} \right )}}{\sqrt {- e^{2}}} & \text {for}\: d^{2} \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- e^{2} x^{2}}} & \text {otherwise} \end {cases}\right )}{16 e^{4}} + \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {d^{4} x}{16 e^{4}} - \frac {d^{2} x^{3}}{24 e^{2}} + \frac {x^{5}}{6}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{5} \sqrt {d^{2}}}{5} & \text {otherwise} \end {cases}\right ) - 2 d e \left (\begin {cases} \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {8 d^{6}}{105 e^{6}} - \frac {4 d^{4} x^{2}}{105 e^{4}} - \frac {d^{2} x^{4}}{35 e^{2}} + \frac {x^{6}}{7}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{6} \sqrt {d^{2}}}{6} & \text {otherwise} \end {cases}\right ) + e^{2} \left (\begin {cases} \frac {5 d^{8} \left (\begin {cases} \frac {\log {\left (- 2 e^{2} x + 2 \sqrt {- e^{2}} \sqrt {d^{2} - e^{2} x^{2}} \right )}}{\sqrt {- e^{2}}} & \text {for}\: d^{2} \neq 0 \\\frac {x \log {\left (x \right )}}{\sqrt {- e^{2} x^{2}}} & \text {otherwise} \end {cases}\right )}{128 e^{6}} + \sqrt {d^{2} - e^{2} x^{2}} \left (- \frac {5 d^{6} x}{128 e^{6}} - \frac {5 d^{4} x^{3}}{192 e^{4}} - \frac {d^{2} x^{5}}{48 e^{2}} + \frac {x^{7}}{8}\right ) & \text {for}\: e^{2} \neq 0 \\\frac {x^{7} \sqrt {d^{2}}}{7} & \text {otherwise} \end {cases}\right ) \]
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Result contains complex when optimal does not.
Time = 0.30 (sec) , antiderivative size = 275, normalized size of antiderivative = 1.38 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d^{4}}{4 \, {\left (e^{6} x + d e^{5}\right )}} + \frac {7 i \, d^{8} \arcsin \left (\frac {e x}{d} + 2\right )}{8 \, e^{5}} + \frac {125 \, d^{8} \arcsin \left (\frac {e x}{d}\right )}{128 \, e^{5}} - \frac {7 \, \sqrt {e^{2} x^{2} + 4 \, d e x + 3 \, d^{2}} d^{6} x}{8 \, e^{4}} + \frac {125 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{6} x}{128 \, e^{4}} - \frac {7 \, \sqrt {e^{2} x^{2} + 4 \, d e x + 3 \, d^{2}} d^{7}}{4 \, e^{5}} - \frac {67 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{4} x}{192 \, e^{4}} + \frac {5 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{5}}{12 \, e^{5}} + \frac {25 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d^{2} x}{48 \, e^{4}} - \frac {4 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d^{3}}{5 \, e^{5}} - \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}} x}{8 \, e^{4}} + \frac {2 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}} d}{7 \, e^{5}} \]
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Time = 0.34 (sec) , antiderivative size = 312, normalized size of antiderivative = 1.56 \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=-\frac {{\left (349440 \, d^{9} e^{9} \arctan \left (\sqrt {\frac {2 \, d}{e x + d} - 1}\right ) \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) + \frac {{\left (1365 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {15}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 61215 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {13}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) + 20517 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {11}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 141159 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {9}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 34969 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {7}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 34853 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {5}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 10465 \, d^{9} e^{9} {\left (\frac {2 \, d}{e x + d} - 1\right )}^{\frac {3}{2}} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right ) - 1365 \, d^{9} e^{9} \sqrt {\frac {2 \, d}{e x + d} - 1} \mathrm {sgn}\left (\frac {1}{e x + d}\right ) \mathrm {sgn}\left (e\right )\right )} {\left (e x + d\right )}^{8}}{d^{8}}\right )} {\left | e \right |}}{1720320 \, d e^{15}} \]
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Timed out. \[ \int \frac {x^4 \left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx=\int \frac {x^4\,{\left (d^2-e^2\,x^2\right )}^{5/2}}{{\left (d+e\,x\right )}^2} \,d x \]
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